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4x^2-15x=14=0
We move all terms to the left:
4x^2-15x-(14)=0
a = 4; b = -15; c = -14;
Δ = b2-4ac
Δ = -152-4·4·(-14)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{449}}{2*4}=\frac{15-\sqrt{449}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{449}}{2*4}=\frac{15+\sqrt{449}}{8} $
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